Optimal. Leaf size=186 \[ \frac{2 a^2 x \sin (c+d x)}{d^2}+\frac{2 a^2 \cos (c+d x)}{d^3}-\frac{a^2 x^2 \cos (c+d x)}{d}+\frac{6 a b x^2 \sin (c+d x)}{d^2}-\frac{12 a b \sin (c+d x)}{d^4}+\frac{12 a b x \cos (c+d x)}{d^3}-\frac{2 a b x^3 \cos (c+d x)}{d}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{24 b^2 x \sin (c+d x)}{d^4}-\frac{24 b^2 \cos (c+d x)}{d^5}-\frac{b^2 x^4 \cos (c+d x)}{d} \]
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Rubi [A] time = 0.320068, antiderivative size = 186, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 4, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.235, Rules used = {6742, 3296, 2638, 2637} \[ \frac{2 a^2 x \sin (c+d x)}{d^2}+\frac{2 a^2 \cos (c+d x)}{d^3}-\frac{a^2 x^2 \cos (c+d x)}{d}+\frac{6 a b x^2 \sin (c+d x)}{d^2}-\frac{12 a b \sin (c+d x)}{d^4}+\frac{12 a b x \cos (c+d x)}{d^3}-\frac{2 a b x^3 \cos (c+d x)}{d}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{24 b^2 x \sin (c+d x)}{d^4}-\frac{24 b^2 \cos (c+d x)}{d^5}-\frac{b^2 x^4 \cos (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 6742
Rule 3296
Rule 2638
Rule 2637
Rubi steps
\begin{align*} \int x^2 (a+b x)^2 \sin (c+d x) \, dx &=\int \left (a^2 x^2 \sin (c+d x)+2 a b x^3 \sin (c+d x)+b^2 x^4 \sin (c+d x)\right ) \, dx\\ &=a^2 \int x^2 \sin (c+d x) \, dx+(2 a b) \int x^3 \sin (c+d x) \, dx+b^2 \int x^4 \sin (c+d x) \, dx\\ &=-\frac{a^2 x^2 \cos (c+d x)}{d}-\frac{2 a b x^3 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}+\frac{\left (2 a^2\right ) \int x \cos (c+d x) \, dx}{d}+\frac{(6 a b) \int x^2 \cos (c+d x) \, dx}{d}+\frac{\left (4 b^2\right ) \int x^3 \cos (c+d x) \, dx}{d}\\ &=-\frac{a^2 x^2 \cos (c+d x)}{d}-\frac{2 a b x^3 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}+\frac{2 a^2 x \sin (c+d x)}{d^2}+\frac{6 a b x^2 \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}-\frac{\left (2 a^2\right ) \int \sin (c+d x) \, dx}{d^2}-\frac{(12 a b) \int x \sin (c+d x) \, dx}{d^2}-\frac{\left (12 b^2\right ) \int x^2 \sin (c+d x) \, dx}{d^2}\\ &=\frac{2 a^2 \cos (c+d x)}{d^3}+\frac{12 a b x \cos (c+d x)}{d^3}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{a^2 x^2 \cos (c+d x)}{d}-\frac{2 a b x^3 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}+\frac{2 a^2 x \sin (c+d x)}{d^2}+\frac{6 a b x^2 \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}-\frac{(12 a b) \int \cos (c+d x) \, dx}{d^3}-\frac{\left (24 b^2\right ) \int x \cos (c+d x) \, dx}{d^3}\\ &=\frac{2 a^2 \cos (c+d x)}{d^3}+\frac{12 a b x \cos (c+d x)}{d^3}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{a^2 x^2 \cos (c+d x)}{d}-\frac{2 a b x^3 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}-\frac{12 a b \sin (c+d x)}{d^4}-\frac{24 b^2 x \sin (c+d x)}{d^4}+\frac{2 a^2 x \sin (c+d x)}{d^2}+\frac{6 a b x^2 \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}+\frac{\left (24 b^2\right ) \int \sin (c+d x) \, dx}{d^4}\\ &=-\frac{24 b^2 \cos (c+d x)}{d^5}+\frac{2 a^2 \cos (c+d x)}{d^3}+\frac{12 a b x \cos (c+d x)}{d^3}+\frac{12 b^2 x^2 \cos (c+d x)}{d^3}-\frac{a^2 x^2 \cos (c+d x)}{d}-\frac{2 a b x^3 \cos (c+d x)}{d}-\frac{b^2 x^4 \cos (c+d x)}{d}-\frac{12 a b \sin (c+d x)}{d^4}-\frac{24 b^2 x \sin (c+d x)}{d^4}+\frac{2 a^2 x \sin (c+d x)}{d^2}+\frac{6 a b x^2 \sin (c+d x)}{d^2}+\frac{4 b^2 x^3 \sin (c+d x)}{d^2}\\ \end{align*}
Mathematica [A] time = 0.266428, size = 101, normalized size = 0.54 \[ \frac{2 d (a+2 b x) \left (a d^2 x+b \left (d^2 x^2-6\right )\right ) \sin (c+d x)-\left (a^2 d^2 \left (d^2 x^2-2\right )+2 a b d^2 x \left (d^2 x^2-6\right )+b^2 \left (d^4 x^4-12 d^2 x^2+24\right )\right ) \cos (c+d x)}{d^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.007, size = 468, normalized size = 2.5 \begin{align*}{\frac{1}{{d}^{3}} \left ({\frac{{b}^{2} \left ( - \left ( dx+c \right ) ^{4}\cos \left ( dx+c \right ) +4\, \left ( dx+c \right ) ^{3}\sin \left ( dx+c \right ) +12\, \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) -24\,\cos \left ( dx+c \right ) -24\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{2}}}+2\,{\frac{ab \left ( - \left ( dx+c \right ) ^{3}\cos \left ( dx+c \right ) +3\, \left ( dx+c \right ) ^{2}\sin \left ( dx+c \right ) -6\,\sin \left ( dx+c \right ) +6\, \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{d}}-4\,{\frac{{b}^{2}c \left ( - \left ( dx+c \right ) ^{3}\cos \left ( dx+c \right ) +3\, \left ( dx+c \right ) ^{2}\sin \left ( dx+c \right ) -6\,\sin \left ( dx+c \right ) +6\, \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{2}}}+{a}^{2} \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) -6\,{\frac{abc \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{d}}+6\,{\frac{{b}^{2}{c}^{2} \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{2}}}-2\,{a}^{2}c \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) +6\,{\frac{ab{c}^{2} \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{d}}-4\,{\frac{{b}^{2}{c}^{3} \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{2}}}-{a}^{2}{c}^{2}\cos \left ( dx+c \right ) +2\,{\frac{ab{c}^{3}\cos \left ( dx+c \right ) }{d}}-{\frac{{b}^{2}{c}^{4}\cos \left ( dx+c \right ) }{{d}^{2}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.07477, size = 548, normalized size = 2.95 \begin{align*} -\frac{a^{2} c^{2} \cos \left (d x + c\right ) + \frac{b^{2} c^{4} \cos \left (d x + c\right )}{d^{2}} - \frac{2 \, a b c^{3} \cos \left (d x + c\right )}{d} - 2 \,{\left ({\left (d x + c\right )} \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right )} a^{2} c - \frac{4 \,{\left ({\left (d x + c\right )} \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right )} b^{2} c^{3}}{d^{2}} + \frac{6 \,{\left ({\left (d x + c\right )} \cos \left (d x + c\right ) - \sin \left (d x + c\right )\right )} a b c^{2}}{d} +{\left ({\left ({\left (d x + c\right )}^{2} - 2\right )} \cos \left (d x + c\right ) - 2 \,{\left (d x + c\right )} \sin \left (d x + c\right )\right )} a^{2} + \frac{6 \,{\left ({\left ({\left (d x + c\right )}^{2} - 2\right )} \cos \left (d x + c\right ) - 2 \,{\left (d x + c\right )} \sin \left (d x + c\right )\right )} b^{2} c^{2}}{d^{2}} - \frac{6 \,{\left ({\left ({\left (d x + c\right )}^{2} - 2\right )} \cos \left (d x + c\right ) - 2 \,{\left (d x + c\right )} \sin \left (d x + c\right )\right )} a b c}{d} - \frac{4 \,{\left ({\left ({\left (d x + c\right )}^{3} - 6 \, d x - 6 \, c\right )} \cos \left (d x + c\right ) - 3 \,{\left ({\left (d x + c\right )}^{2} - 2\right )} \sin \left (d x + c\right )\right )} b^{2} c}{d^{2}} + \frac{2 \,{\left ({\left ({\left (d x + c\right )}^{3} - 6 \, d x - 6 \, c\right )} \cos \left (d x + c\right ) - 3 \,{\left ({\left (d x + c\right )}^{2} - 2\right )} \sin \left (d x + c\right )\right )} a b}{d} + \frac{{\left ({\left ({\left (d x + c\right )}^{4} - 12 \,{\left (d x + c\right )}^{2} + 24\right )} \cos \left (d x + c\right ) - 4 \,{\left ({\left (d x + c\right )}^{3} - 6 \, d x - 6 \, c\right )} \sin \left (d x + c\right )\right )} b^{2}}{d^{2}}}{d^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.72934, size = 270, normalized size = 1.45 \begin{align*} -\frac{{\left (b^{2} d^{4} x^{4} + 2 \, a b d^{4} x^{3} - 12 \, a b d^{2} x - 2 \, a^{2} d^{2} +{\left (a^{2} d^{4} - 12 \, b^{2} d^{2}\right )} x^{2} + 24 \, b^{2}\right )} \cos \left (d x + c\right ) - 2 \,{\left (2 \, b^{2} d^{3} x^{3} + 3 \, a b d^{3} x^{2} - 6 \, a b d +{\left (a^{2} d^{3} - 12 \, b^{2} d\right )} x\right )} \sin \left (d x + c\right )}{d^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.59693, size = 228, normalized size = 1.23 \begin{align*} \begin{cases} - \frac{a^{2} x^{2} \cos{\left (c + d x \right )}}{d} + \frac{2 a^{2} x \sin{\left (c + d x \right )}}{d^{2}} + \frac{2 a^{2} \cos{\left (c + d x \right )}}{d^{3}} - \frac{2 a b x^{3} \cos{\left (c + d x \right )}}{d} + \frac{6 a b x^{2} \sin{\left (c + d x \right )}}{d^{2}} + \frac{12 a b x \cos{\left (c + d x \right )}}{d^{3}} - \frac{12 a b \sin{\left (c + d x \right )}}{d^{4}} - \frac{b^{2} x^{4} \cos{\left (c + d x \right )}}{d} + \frac{4 b^{2} x^{3} \sin{\left (c + d x \right )}}{d^{2}} + \frac{12 b^{2} x^{2} \cos{\left (c + d x \right )}}{d^{3}} - \frac{24 b^{2} x \sin{\left (c + d x \right )}}{d^{4}} - \frac{24 b^{2} \cos{\left (c + d x \right )}}{d^{5}} & \text{for}\: d \neq 0 \\\left (\frac{a^{2} x^{3}}{3} + \frac{a b x^{4}}{2} + \frac{b^{2} x^{5}}{5}\right ) \sin{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.11363, size = 173, normalized size = 0.93 \begin{align*} -\frac{{\left (b^{2} d^{4} x^{4} + 2 \, a b d^{4} x^{3} + a^{2} d^{4} x^{2} - 12 \, b^{2} d^{2} x^{2} - 12 \, a b d^{2} x - 2 \, a^{2} d^{2} + 24 \, b^{2}\right )} \cos \left (d x + c\right )}{d^{5}} + \frac{2 \,{\left (2 \, b^{2} d^{3} x^{3} + 3 \, a b d^{3} x^{2} + a^{2} d^{3} x - 12 \, b^{2} d x - 6 \, a b d\right )} \sin \left (d x + c\right )}{d^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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